1/4a^2=10

Solution for 1/4a^2=10 equation:

1/4a^2=10

We move all terms to the left:

1/4a^2-(10)=0


Domain of the equation: 4a^2!=0

a^2!=0/4

a^2!=√0

a!=0

a∈R


We multiply all the terms by the denominator


-10*4a^2+1=0

Wy multiply elements

-40a^2+1=0

a = -40; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-40)·1
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*-40}=\frac{0-4\sqrt{10}}{-80}
=-\frac{4\sqrt{10}}{-80}
=-\frac{\sqrt{10}}{-20}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*-40}=\frac{0+4\sqrt{10}}{-80}
=\frac{4\sqrt{10}}{-80}
=\frac{\sqrt{10}}{-20}
$